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15 December, 17:26

Given that p varies directly as the square of q and p equal 12 when q equal 3 find the value of p when q equal 5

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  1. 15 December, 19:08
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    p = 100/3

    Step-by-step explanation:

    P varies directly as q^2 and

    p = k q^2

    We know p = 12 and q = 3, we can solve for k

    12 = k 3^2

    12 = k*9

    Divide by 9

    12/9 = k

    4/3 = k

    p = 4/3 q^2

    When q = 5

    p = 4/3 * 5^2

    p = 4/3*25

    p = 100/3
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