Use the Quadratic Formula to solve

x²-13x+42=0

x1=7,

x2=6

Step-by-step explanation:

x²-13x+42=0

a=1, b=-13, c=42

x1,2 = (-b+-sqrt (b^2-4ac)) / 2a

x1,2 = ( - (-13) + -sqrt ((-13) ^2-4*1*42)) / 2*1

x1,2 = (13+-sqrt (169-168)) / 2

x1,2 = (13+-sqrt (1)) / 2

x1,2 = (13+-1) / 2

x1 = (13+1) / 2, x2 = (13-1) / 2

x1=14/2, x2=12/2

x1=7, x2 = 6