the diagram shows a right angled triangle. its hypotenuese is (x+4) cm while tge lengths of the otger two sides are x cm and (2x-y) cm respectively. If the perimeter of the triangle is 24 cm, find the value of x and of y with the condition x> y

Sum of all sides of triangle = perimeter of it

x+4+x+2x-y=24

4x-y=20

y=4x-20

H^2=p^2+b^2

(x+4) ^2=x^2 + (-2x+20) ^2

From here you can calculate value of x and y

x^2+16+8x=5x^2-80x+400

4x^2-88x+384

=x^2-22x+96

you use quadratic formula to calculate x and y

Remember greatest value should be x and smallest should be y as the conditions given above