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9 July, 17:57

Express the solution of, x^3 + 2x^2 < x + 2, using interval notation.

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  1. 9 July, 19:13
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    x³ + 2x² - x - 2 < 0

    x³ - x + 2x² - 2 < 0

    x (x² - 1) - 2 (x² - 1) < 0

    (x - 2) (x² - 1) < 0

    (x - 2) (x - 1) (x + 1) < 0

    by chacking we get the solution

    x ∈ (-∞,-1) ∪ (-1,1)
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