Ask Question
20 March, 00:34

A box contains 4 white balls and 5 red balls. I draw 3 of them out of the box, one at a time, without replacement. What is the probability that the balls I draw alternate between the two colors?

+1
Answers (1)
  1. 20 March, 04:22
    0
    Let A be the probability of drawing a white ball first, then a red one second, and then a white one last.

    Let B be the probability of drawing a red ball first, then a white one second, and then a red one last.

    So, P (A or B) =

    [4/9 x 5/8 x 3/7 = 60/504 ] + [ 5/9 x 4/8 x 4/7 = 80/504 ] =

    [60 + 80 ] / 504 = 140/504 = 5/18 = about 27.8%
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A box contains 4 white balls and 5 red balls. I draw 3 of them out of the box, one at a time, without replacement. What is the probability ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers