Two trucks leave a warehouse at the same time. One travels due south at an average speed of 59 59 miles per hour, and the other travels due north at an average speed of 62 62 miles per hour. After how many hours will the two trucks be 665.5 665.5 miles apart?

Step-by-step explanation:

D=R*T

d=665.5

r = (59+62) / 2

665.5 = (59+62) / 2*T

665.5=60.5*t

t=11

each driver drove 5.5 hours.

5 hours 30 minutes

Step-by-step explanation:

Truck one is traveling south at 59 mph

It'd distance can be expressed as

d = 59t with d being the distance traveled, 59 is the speed, and t is

the number of hours it traveled for

Truck two is traveling north at 62 mph

It'd distance can be expressed as

d = 62t with d being the distance traveled, 62 is the speed, and t is

the number of hours it traveled for

We want their combined distance to be 665.5, so use the equation

59t + 62t = 665.5 and solve for t

121t = 665.5 (combine like terms on the left)

t = 665.5/121 (divide be 121 on both sides to isolate the

variable)

t = 5.5 (simplify)

t = 5 hours 30 minutes (0.5 hours is 30 minutes)