Their perimeter of a triangle is 82' one side of the triangle is 2 times the 2nd side the 3rd side is 2' longer than the 2nd side find the length of each side

side 1: 40; side 2: 20; side 3: 22

Step-by-step explanation:

It appears that sides 1 and 3 are based on side 2. So side 2 is our "control" and we'll call it x.

If side 1 is 2 times side 2, then

side 1 = 2x.

If side 3 is 2 feet longer than side 2, then

side 3 = x + 2

We are given the perimeter value. The perimeter of any shape is a measure around the outside of the shape. Since a triangle has 3 sides, we add them together and set their sum equal to the perimeter we were given. That looks like this:

x + 2x + x + 2 = 82

Combine like terms to get 4x + 2 = 82

Solve for x to get 4x = 80 and x = 20. That means that side 2 measures 20 feet; side 1 measures twice that, so side 1 = 40 feet, and side 3 measures 2 more than side 2, so side 3 measures 22. Let's add them all together and make sure the numbers work:

20 + 40 + 22 = 82

It works! So we're all done!