Amelia and Barrett sold a total of 137 raffle tickets at the football game. Barrett sold 10 fewer than twice as many as Amelia. How many tickets did Barrett sell?

Barett Sold 88 Tickets

Step-by-step explanation:

To Start off we are told that the Total of tickets sold between Amelia (A) and Barrett (B) was 137.

Total = 137

Since Barett Sold 10 less than twice as many tickets as Amelia, we can make the following equation, where Barett is B and Amelia is A.

A + B = 137

A + (2A-10) = 137 (Barett equalls 10 less than twice Amelia)

Now we can solve the equation for A

A + (2A-10) = 137

3A - 10 = 137 (Combine Like Terms)

3A = 147 (add 10 on both sides)

A = 49 (divide by 3 on both sides)

Now that we have the amount of tickets that Amelia sold we can plug it in for B to find out how many tickets Barett Sold

(2A-10) = B

(2*49) - 10 = B

(2A-10) = B

98 - 10 = B

88 = B