what are the possible values of x in 8x^2+4=-1 a. 2+-iroot/3 b. - 1+-i/6 c.-1+-i/4 d. 1+-i/4 e. 1+-i root 2/4

x = ± i sqrt (5/8)

Step-by-step explanation:

8x^2+4=-1

Subtract 4 from each side

8x^2+4-4=-1-4

8x^2 = - 5

Divide by 8

8/8x^2=-5/8

x^2 = - 5/8

Take the square root of each side

sqrt (x^2) = ±sqrt (-5/8)

x = ±sqrt (-5/8)

x = ±sqrt (5/8) sqrt (-1)

x = ± i sqrt (5/8)