A bottle contained 1600 ml milk. Ben poured it into 2 cups.

Cup A contained 60% of the milk. If 40% of the milk in cup A

and 70% of the milk in cup B had been drank. How much

more milk had been drank from cup B than cup A?

_ml

Question

Mathematics

Kenyon Good

4 April, 00:38

A bottle contained 1600 ml milk. Ben poured it into 2 cups.

Cup A contained 60% of the milk. If 40% of the milk in cup A

and 70% of the milk in cup B had been drank. How much

more milk had been drank from cup B than cup A?

_ml

+4

Answers (1)

Know the Answer?

Brenda Hayes · Answer 1

Step-by-step explanation:

cup A = 60% of milk

= 60% * 1600 ml

= 960 ml

cup B = 1600 ml - 960 ml

= 640 ml

milk drank from cup A

= 40% * 960

= 384 ml

milk drank from cup B

= 70% * 640

= 448 ml

how much more milk from cup B had been drank?

= 448 ml - 384 ml

= 64 ml

A bottle contained 1600 ml milk. Ben poured it into 2 cups.Cup A contained 60% of the milk. If 40% of the milk in cup Aand 70% of the milk in cup B had been drank. How muchmore milk had been drank from cup B than cup A?_ml

A bottle contained 1600 ml milk. Ben poured it into 2 cups.

Cup A contained 60% of the milk. If 40% of the milk in cup A

and 70% of the milk in cup B had been drank. How much

more milk had been drank from cup B than cup A?

_ml