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13 August, 05:10

A driver took a day-trip at two different speeds. He drove 100 miles at a slower speed and 240 miles at a speed 10 miles per hour faster. If the time spent during the faster speed was twice that spent at a slower speed, find the two speeds during the trip

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  1. 13 August, 06:46
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    So, time faster = 2 · time slower;

    We have formula: time slower = 100 / slower speed;

    time faster = 240 / (10 + slower speed);

    Then, 240 / (10 + slower speed) = 2 · (100 / slower speed);

    Let slower speed be x;

    We solve the equation: 240 / (10 + x) = 2 · (100 / x);

    240 / (10 + x) = 200 / x;

    240x = 200 (10 + x);

    240x = 2000 + 200x;

    40x = 2000;

    x = 50 miles per hour (the slower speed);

    The faster speed: 50 + 10 = 60 miles per hour.
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