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27 March, 18:31

If sec0+tan0=p, then find the value of cosec0.

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  1. 27 March, 19:51
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    Step-by-step explanation:

    p=sec0+tan0

    =1/cos0 + sin0/cos0

    = (1+sin0) / cos0

    square both sides

    (1+sin) ^2 / cos^2 = p^2

    (1+sin) ^2 / (1 - sin^2) = p^2

    (1+sin) ^2 / ((1-sin) (1+sin)) = p^2

    (1+sin) / (1-sin) = p^2

    1+sin=p^2-p^sin

    sin+p^2sin=p^2-1

    sin (1+p^2) = (p^2-1)

    sin = (1-p^2) / (1+p^2)

    cosec=1/sin

    = (1+p^2) / (1-p^2)
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