Which of the following equations would represent the graph of the parabola y=3x^2-4x-1 after a reflection in the x-axis?

Answer: The reflection is: y' = - 3x^2 + 4x - 1

Step-by-step explanation:

We have the parabola y = 3x^2 - 4x + 1

When we do a reflection in one of the two principal axis (x-axis or y-axis), the thing we need to do is multiply the other variable by - 1 (if the reflection is done in the x-axis, we multiply y by - 1)

We have that our new graph is the graph of - 1*y, and this is = - 1 * (3x^2 - 4x + 1)

The reflection is: y' = - 3x^2 + 4x - 1