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2 April, 22:29

Degree 3 polynomial with integer coefficients with zeros 7i and 9/5 Write it as a polynomial

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  1. 3 April, 00:08
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    f (x) = 5x^3 - 9x^2 + 245x - 441.

    Step-by-step explanation:

    Complex zeros are in conjugate pairs so the third zero is - 7i.

    In factor form we have:

    f (x) = (x - 7i) (x + 7i) (5x - 9)

    = (x^2 - 49i) ^2) (5x - 9)

    = (x^2 + 49) (5x - 9)

    = 5x^3 - 9x^2 + 245x - 441.
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