Degree 3 polynomial with integer coefficients with zeros 7i and 9/5 Write it as a polynomial

f (x) = 5x^3 - 9x^2 + 245x - 441.

Step-by-step explanation:

Complex zeros are in conjugate pairs so the third zero is - 7i.

In factor form we have:

f (x) = (x - 7i) (x + 7i) (5x - 9)

= (x^2 - 49i) ^2) (5x - 9)

= (x^2 + 49) (5x - 9)

= 5x^3 - 9x^2 + 245x - 441.