Four people, in turn, are going to choose a marble randomly from a jar containing nine marbles, labeled 1 2 3 4 5 6 7 8 9. Each person will replace his/hers marble after choosing. In how many ways can these four people choose?

Sorry this is a write in not a multiple choice!

Question

Mathematics

Braeden

19 December, 09:48

Four people, in turn, are going to choose a marble randomly from a jar containing nine marbles, labeled 1 2 3 4 5 6 7 8 9. Each person will replace his/hers marble after choosing. In how many ways can these four people choose?

Sorry this is a write in not a multiple choice!

+4

Answers (1)

Know the Answer?

Hank · Answer 1

Answer: 36 ways

Step-by-step explanation:

This is probability with replacement

Each of them want to choose a marble randomly from a jar containing nine marbles

The number of ways these four people can choose will be

4 (9 combination 1) that is

4 (9C1) = 4[9! / (9-1) ! 1!]

= 4[9!/8!]

= 4 (9)

= 36 ways

Four people, in turn, are going to choose a marble randomly from a jar containing nine marbles, labeled 1 2 3 4 5 6 7 8 9. Each person will replace his/hers marble after choosing. In how many ways can these four people choose?Sorry this is a write in not a multiple choice!

Four people, in turn, are going to choose a marble randomly from a jar containing nine marbles, labeled 1 2 3 4 5 6 7 8 9. Each person will replace his/hers marble after choosing. In how many ways can these four people choose?

Sorry this is a write in not a multiple choice!