Ask Question
8 February, 14:41

Farmer bob was counting his cows and chickens and saw that there was 54 legs all together if he had 20 cows and chickens how many of each did he have?

+5
Answers (1)
  1. 8 February, 18:14
    0
    Answer: <3

    7 cows and 13 chickens

    Step-by-step explanation:

    System of Equations:

    x = cows

    y = chickens

    x + y = 20 - -> y = - x + 20

    4x + 2y = 54

    substitute:

    4x + 2 (-x + 20) = 54

    4x - 2x + 40 = 54

    2x = 14

    x = 7 cows

    Now we plug in x to get y.

    7 + y = 20

    y = 13 chickens
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Farmer bob was counting his cows and chickens and saw that there was 54 legs all together if he had 20 cows and chickens how many of each ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers