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17 October, 19:38

if n represent number than write an expression for three times the difference of the number amd six increased by four times the number

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  1. 17 October, 21:47
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    Let n be the number. The difference of the number and six is n-6. Then three times the difference of the number and six is 3· (n-6). This number 3· (n-6) increased by four times the number n, then

    3· (n-6) = 4·n.

    Solve it:

    3·n-3·6=4n,

    3n-4n=18,

    -n=18,

    n=-18.

    Answer: n=-18 and expression is 3· (n-6) = 4·n.
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