What is the answer to 8 (s^2+2s+3) + (2s+s+1)

s = (i sqrt (439)) / 16 - 19/16 or s = - (i sqrt (439)) / 16 - 19/16

Step-by-step explanation:

Solve for s:

1 + 3 s + 8 (s^2 + 2 s + 3) = 0

Expand out terms of the left hand side:

8 s^2 + 19 s + 25 = 0

Divide both sides by 8:

s^2 + (19 s) / 8 + 25/8 = 0

Subtract 25/8 from both sides:

s^2 + (19 s) / 8 = - 25/8

Add 361/256 to both sides:

s^2 + (19 s) / 8 + 361/256 = - 439/256

Write the left hand side as a square:

(s + 19/16) ^2 = - 439/256

Take the square root of both sides:

s + 19/16 = (i sqrt (439)) / 16 or s + 19/16 = - (i sqrt (439)) / 16

Subtract 19/16 from both sides:

s = (i sqrt (439)) / 16 - 19/16 or s + 19/16 = - (i sqrt (439)) / 16

Subtract 19/16 from both sides:

Answer: s = (i sqrt (439)) / 16 - 19/16 or s = - (i sqrt (439)) / 16 - 19/16