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1 August, 13:15

In a newspaper, it was reported that yearly robberies in Springfield were up 50% to 93 in 2013 from 2012. How many robberies were there in Springfield in 2012?

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  1. 1 August, 14:15
    0
    There were 62 deaths

    Step-by-step explanation:

    In this question, we are asked to calculate the number of robberies in 2012.

    From the question we can identify that the number of robberies were up 50% to 93. What this means is that the number is simply 150% of the old number.

    Now, let's represent the number of deaths in 2012 by x

    Mathematically;

    150% of x = 93

    150/100 * x = 93

    150x = 93 * 100

    150x = 9300

    x = 9300/150

    x = 62

    This means there were 62 deaths in the year 2012
  2. 1 August, 15:33
    0
    There were 62 robberies in Springfield in 2012.

    Step-by-step explanation:

    Let's marked (named) robberies in 2012 with x, which is worth 100%

    93 robberies in 2013 worth 100% + 50% = 150%

    Now we will make proportion

    x : 93 = 100 : 150

    When we multiply external and internal members we get

    x/93 = 100/150

    Cross multiply

    150 x = 93 * 100

    150x = 9300

    x = 9300/150

    x = 62 robberies in 2012
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