What is the product (40 + (-10)) ((36 + (-9)) (32 + (-8)) ... (-32 + 8) (-36 + 9) (-40 + 10) where the first number in each factor is decreasing by 4 and second number in each factor is increasing by 1?

Question

Mathematics

Abel Mcgee

6 March, 06:24

What is the product (40 + (-10)) ((36 + (-9)) (32 + (-8)) ... (-32 + 8) (-36 + 9) (-40 + 10) where the first number in each factor is decreasing by 4 and second number in each factor is increasing by 1?

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Answers (1)

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Melina Ramsey · Answer 1

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Step-by-step explanation:

The first number is 40 and decreases by 4 in each factor, and the second number is - 10 and increases by 1 in each factor.

The first number is positive and decreases by 10% its value in each factor, and the second number is negative and increases by 10% its absolute value in each factor. That means we will have a factor where both numbers are 0 (in the 11th value, we will have the first number 40 - 4*10 = 0 and the second number - 10 + 1*10 = 0), so the factor will be 0 + 0 = 0, and then whole product will be zero.