A single six-sided fair die is tossed, what is the probability of obtaining a number greater than 4?

1/3 or 0.333333

Step-by-step explanation:

The question talks about a die that was tossed once and we are now asked to find the probability that it is a figure greater than 4

---A die has 6 faces with the numbers 1,2,3,4,5 and 6 one on each of

the six faces. Considering an unbaised die the probability of any of the faces to appear in a single roll is 1/6.

So, P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = 1/6

Now that numbers greater than 4 are 5 and 6

So it can be P (5) or P (6) = P (5) + P (6) = 2/6 = 1/3 or 0.33333

Answer 1/3 or 0.33333