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28 July, 08:02

The vertex form of the equation of a parabola is y = (x+3) ^2+53. what is the standard form?

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  1. 28 July, 09:33
    0
    "Standard form" appears like y = ax^2 + bx + c.

    Starting with y = (x+3) ^2+53, perform the indicated exponentiation / multiplication:

    y = x^2 + 6x + 9 + 53.

    Combining the constants, we get

    y = x^2 + 6x + 62, which is the equation of a parabola in standard form.
  2. 28 July, 10:28
    0
    y = x² + 6x + 62 ~apex I did it and it is correct
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