How do you solve, 3r+2 (12r+7) less then or equal to 5r-8

r ≤ - 1

Step-by-step explanation:

Given in the question

3r+2 (12r+7) ≤ 5r-8It can be solve by Simplifying and Reordering the terms

3r + 2 (12r) + 2 (7) ≤ 5r - 8

3r + 24r + 14 ≤ 5r - 8

27r + 14 ≤ 5r - 8

27r - 5r + 14 + 8 ≤ 0

22r + 22 ≤ 0

22r ≤ - 22

Move term containing r to the left, all term to the right.

r ≤ - 22/22

simplifying

r ≤ - 1

all negative integers which are smaller than or equal to - 1