A circle has the equation x2+y2+16y-30x=0.

What is the equation of the circle in standard form, the coordinates of its center, and the length of its radius?

The equation of the circle is (x+15) 2 + (y-8) 2=289; the center is at (-15,8), and the radius is 17 units.

The equation of the circle is (x-15) 2 + (y+8) 2=289; the center is at (-15,8), and the radius is 289 units.

The equation of the circle is (x-15) 2 + (y+8) 2=289; the center is at (15,-8), and the radius is 17 units.

The equation of the circle is (x-15) 2 + (y+8) 2=289; the center is at (15,-8), and the radius is 289 units.

Question

Mathematics

Dashawn Villegas

22 May, 07:44

A circle has the equation x2+y2+16y-30x=0.

What is the equation of the circle in standard form, the coordinates of its center, and the length of its radius?

The equation of the circle is (x+15) 2 + (y-8) 2=289; the center is at (-15,8), and the radius is 17 units.

The equation of the circle is (x-15) 2 + (y+8) 2=289; the center is at (-15,8), and the radius is 289 units.

The equation of the circle is (x-15) 2 + (y+8) 2=289; the center is at (15,-8), and the radius is 17 units.

The equation of the circle is (x-15) 2 + (y+8) 2=289; the center is at (15,-8), and the radius is 289 units.

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Answers (1)

Know the Answer?

Laylah Klein · Answer 1

Step-by-step explanation:

hello:

x2+y2+16y-30x=0 means : (x²-30x) + (y²+16y) = 0

(x²-30x+15²) - 15² + (y²+16y+8²) - 8²=0

(x-15) ²-225 + (y+8) ²-64=0

(x-15) ² + (y+8) ²=289=17² ... standard form when the center is (15, - 8)

and radius 17