What values of b satisfy 4 (3b + 2) 2 = 64?

A. b = 2/3 and b = - 2

B. b = 2 and b = 10/3

C. b = 2/3 and b = 3

D. b = 2 and b = - 10/3

Given the equation 4 (3b + 2) ² = 64, dividing both sides of the equation by 4, we have (3b + 2) ² = 16 and getting the square root of both sides, (3b + 2) = 4 and (3b + 2) = - 4 We can solve for b for each equation and have 3b = 2 | 3b = - 6 b = 2/3 | b = - 2 Therefore, the values of b are 2/3 and - 2 and from the choices, the answer is A: b = 2/3 and b = - 2.