A campus club held a bake sale as a fund raiser, selling coffee, muffins, and bacon and eggs sandwiches. The club members charged $1 for a cup of coffee, 3$ for a muffin, and $4 for a back. And egg sandwich. They sold a total of 55 items, easing $119. Of the club members sold 5 more muffins than cups of coffee, how many bacon and egg sandwiches he's did they sell

The number of bacon and egg sandwiches sells are 2.

Step-by-step explanation:

Let us assume that the number of coffee cups campus club sells be x.

Let us assume that the number of muffins cups campus club sells be y.

Let us assume that the number of bacon and eggs sandwiches campus club sells be z.

As given

Campus club sold a total of 55 items.

Thus the equation becomes

x + y + z = 55

Of the club members sold 5 more muffins than cups of coffee.

Thus

Number of muffins = 5 + Number of cups of coffee

y = 5 + x

Putting the value of y in the equation x + y + z = 55.

x + 5 + x + z = 55

2x + z = 55 - 5

2x + z = 50

As given

The club members charged $1 for a cup of coffee, 3$ for a muffin, and $4 for a bacon and egg sandwich and earns $119.

Thus the equation becomes

x + 3y + 4z = 119

Putting the value of y in the above

x + 3 * (x + 5) + 4z = 119

x + 3x + 15 + 4z = 119

4x + 4z = 119 - 15

4x + 4z = 104

Simplify the above

x + z = 26

Thus the two equations are

2x + z = 50

x + z = 26

Multiply x + z = 26 subtracted from 2x + z = 50.

2x - x + z - z = 50 - 26

x = 24

Put the value of x in x + z = 26.

24 + z = 26

z = 26 - 24

z = 2

Therefore the number of bacon and egg sandwiches sells are 2.