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23 December, 04:21

Prove this trigonometric identity

sin 3x/sin x - cos 3x/cos x = 2

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Answers (1)
  1. 23 December, 05:28
    0
    Step-by-step explanation:

    LHS = sin 3x/sin x - cos 3x/cosx

    Taking LCM,

    =sin3xcosx - cos3xsinx

    sinxcosx

    =sin (3x-x)

    sinxcosx

    = 2sin2x

    2sinxcosx

    = 2sin2x

    sin2x

    =2

    = RHS.

    Proved.
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