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29 July, 05:21

Find the Larget of the three consecutive integers such as 3 times the sum of the first and third integer is equal to 30 more than 4 times the second integer

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  1. 29 July, 06:58
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    first integer: x

    second integer: x + 1

    third integer: x + 2

    3[ (x) + (x + 2) ] = 4 (x + 1) + 30

    3 (2x + 2) = 4 (x + 1) + 30

    6x + 6 = 4x + 4 + 30

    6x + 6 = 4x + 34

    2x + 6 = 34

    2x = 28

    x = 14

    Answer: 14, 15, 16
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