Solve the quadratic a (^ means to the power of)

1) K^2 - 12k = 0

2) X^2 - 19x = 0

Question

Mathematics

Amiga

31 August, 07:38

Solve the quadratic a (^ means to the power of)

1) K^2 - 12k = 0

2) X^2 - 19x = 0

+5

Answers (1)

Know the Answer?

Nathan Jordan · Answer 1

K^2-12k=0

k (k-12) = 0

set to zero

k=0

k-12=0

k=12

k=0 or 12

2.

x^2-19x=0

x (x-19) = 0

set to zer o

x=0

x-19=0

x=19

x=0 or 19

1. x=0 or 12

2. x=0 or 19

Solve the quadratic a (^ means to the power of)1) K^2 - 12k = 02) X^2 - 19x = 0

Solve the quadratic a (^ means to the power of)

1) K^2 - 12k = 0

2) X^2 - 19x = 0