What is the vertex of y=2x^2+12x+22

The x value of the vertex for

ax²+bx+c=y is - b/2a

so

y=2x²+12x+22

b=12

a=2

-b/2a=-12 / (2*2) = - 12/4=-3

that is x value

to find y value, sub the x value for x

-3 for x

y=2 (-3) ²+12 (-3) + 22

y=2 (9) - 36+22

y=18-14

4

(-3,4) is vertex