A rectangle has a length of 11 meters less than 10 times its width. If the area of the rectangle is 9888 square meters, find the length of the rectangle.

Step-by-step explanation:

The Length,

L

=

284

f

t

.

Explanation:

Given:

Rectangle

Area,

A

=

8804

f

t

2

let W bet he width of the rectangle

L be the length of the rectangle

L

=

10

W

-

26

E

q

u

a

t

i

o

n

1

substitute to

e

q

u

a

t

i

o

n

2

A

=

(

L

)

(

W

)

e

q

u

a

t

i

o

n

2

A

=

(

10

W

-

26

)

(

W

)

8804

=

(

10

W

-

26

)

(

W

)

factor

8804

=

2

(

5

W

-

13

)

(

W

)

divide both sides by 2

4402

=

(

5

W

-

13

)

(

W

)

4402

=

5

W

2

-

13

W

transposing 4402 to the right side of the equation

0

=

5

W

2

-

13

W

-

4402

by quadratic formula

W

=

-

(

-

13

)

+

√

(

-

13

)

2

-

4

(

5

)

(

-

4402

)

2

(

5

)

W

=

[

13

+

√

169

+

88040

]

10

W

=

13

+

(

√

88209

)

10

W

=

13

+

297

10

W

=

310

10

W

=

31

ft

Thus,

L

=

10

W

-

26

=

10

(

31

)

-

26

L

=

284

f

t

.

answer

W

=

-

(

-

13

)

-

√

-

(

-

13

2

)

-

4

(

5

)

(

-

4402

)

2

(

5

)

this is discarded since this will yield a negative