Ben wants to try a new restaurant for dinner. His online search

resulted in 7 new 3-star restaurants, 5 new 4-star restaurants, and 3

new 5-star restaurants. If he were to choose a restaurant at random,

what is the probability that he chooses a 5-star restaurant?

Select one:

33%

20%

47%

3%

Question

Mathematics

Jordon Walters

2 December, 03:51

Ben wants to try a new restaurant for dinner. His online search

resulted in 7 new 3-star restaurants, 5 new 4-star restaurants, and 3

new 5-star restaurants. If he were to choose a restaurant at random,

what is the probability that he chooses a 5-star restaurant?

Select one:

33%

20%

47%

3%

+1

Answers (2)

Know the Answer?

Steven Oliver · Answer 1

It would be about 3% I got this because you first had to multiply the results by the amount of stars they had so like 7*3 is 21 and so on if you did this to all the pairs you would get 56 now divide 56 by the amount of restaurants 7+5+3 which is 15 so 56 divided by 15 is about 3%

Jayden · Answer 2

Ben found:

7 ⭐️⭐️⭐️ restaurants

5 ⭐️⭐️⭐️⭐️ restaurants

3 ⭐️⭐️⭐️⭐️⭐️ restaurants

A total of 15 restaurants

Out of the 15 restaurants, 3 will be 5-star. So, 3/15, reduces to 1/5 and 1/5 as a percentage is 20%

Ben's probability of choosing a 5-star restaurant at random is 20%

Ben wants to try a new restaurant for dinner. His online searchresulted in 7 new 3-star restaurants, 5 new 4-star restaurants, and 3new 5-star restaurants. If he were to choose a restaurant at random,what is the probability that he chooses a 5-star restaurant?Select one:33%20%47%3%

Ben wants to try a new restaurant for dinner. His online search

resulted in 7 new 3-star restaurants, 5 new 4-star restaurants, and 3

new 5-star restaurants. If he were to choose a restaurant at random,

what is the probability that he chooses a 5-star restaurant?

Select one:

33%

20%

47%

3%