A parabola has a vertex at (-3,2). Where is the axis of symmetry?

The axis of symmetry of the parabola with a vertex at (-3, 2) is at

x = - 1/2

Step-by-step explanation:

Given a quadratic function (parabola) of the form:

y = ax² + bx + c

The axis of symmetry of the function is a vertical line that divides the parabola into two congruent halves. The x-coordinate of the vertex is the equation of the axis of symmetry of the parabola.

This is given as x = - b/2a

We are given a parabola with vertex at (-3, 2). The quadratic function corresponding to this is

y = (x - (-3)) (x - 2)

= (x + 3) (x - 2)

= x² - 2x + 3x - 6

y = x² + x - 6

Here, a = 1, b = 1, and c = - 6

The axis of symmetry is at

x = - b/2a

= - 1/2 (1)

= - 1/2