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20 October, 03:49

Which polynomial function has a leading coefficient of 1, roots - 2 and 7 with multiplicity 1, and root 5 with multiplicity 27

O

f (x) = 2 (x + 7) (x + 5) (x-2)

Rx) = 2 (x - 7) (x - 5) (x + 2)

Rx) = (x + 7) (x + 5) (x + 5) (x - 2)

f (x) = (x - 7) (x - 5) (x - 5) (x + 2)

Answers (1)
  1. J
    20 October, 06:04
    0
    The polynomial that has a leading coefficient of 1, roots - 2 and 7 with multiplicity 1, and root 5 with multiplicity of 2 is f (x) = (x - 7) (x - 5) (x - 5) (x + 2)

    Step-by-step explanation:

    From the question, the polynomials are factorized, we therefore analyze each one as follows

    1) f (x) = 2 (x + 7) (x + 5) (x - 2)

    Roots are - 7, - 5 and 2

    2) R (x) = 2 (x - 7) (x - 5) (x + 2)

    Roots are 7, 5 and - 2 the root 5 has multiplicity 1

    3) R (x) = (x + 7) (x + 5) (x + 5) (x - 2)

    Roots are - 7, - 5 multiplicity 2 and 2

    4) f (x) = (x - 7) (x - 5) (x - 5) (x + 2)

    Roots are - 2 and 7, both with multiplicity 1, 5 with multiplicity 2 and coefficient of 1

    Hence 4 is the required polynomial.
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