Plane B is flying 60mph faster than Plane A and can fly 3040 miles in the same amount of time it takes Plane A to fly 2800 miles. Find the amount of time it takes for each plane to travel their respective distances.

Answer: each plane travelled for 40 hours.

Step-by-step explanation:

Let x represent the speed of plane A. Plane B is flying 60mph faster than Plane A. It means that the speed at which plane B is flying is

(x + 60) mph

Plane B can fly 3040 miles in the same amount of time it takes Plane A to fly 2800 miles.

Time = distance/speed

Time taken by plane B to fly 3040 miles is

3040 / (x + 60)

Time taken by plane A to fly 2800 miles is

2800/x

Since the time is the same, it means that

3040 / (x + 60) = 2800/x

Cross multiplying, it becomes

2800 (x + 6) = 3040x

2800x + 16800 = 3040x

3040x - 2800x = 16800

240x = 16800

x = 16800/240

x = 70 mph

The amount of time it takes for each plane to travel their respective distances is

2800/x = 2800/70 = 40 hours