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14 December, 13:38

Sue either travels by bus or walks when she visits the shops. The probability that she catches the bus to the shops is 0.4. The probability that she catches the bus from the shop is 0.7. Show the probability that sue walks at least one way is 0.72

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  1. 14 December, 15:46
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    Answer: P (A∪B) = 0.72. The answer is provided below.

    Step-by-step explanation:

    Sue travels by bus or walks whenever she goes to the shops.

    Probability of (catching the bus to shop), P (A) = 0.4

    Probability of (catching the bus from the shop), P (B) = 0.7

    Both of the events A and B are independent events.

    Therefore, P (A∩B) = 0.4 * 0.7

    = 0.28

    Probability that Sue walks one way will be = 1 - P (A∩B)

    = 1 - 0.28

    = 0.72

    Hence, the probability that Sue will walk at one way is 0.72
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