Solve each system of equations by using substitution.

A. y = - x + 5

x + 2y = 2

B. 4y - x = - 2

y = 3x + 5

Step-by-step explanation:

A. x + 2 (-x + 5) = 2

x + - 2x + 10 = 2

-x = - 8

x = 8

y = - 8 + 5 = - 3

B. 4 (3x + 5) - x = - 2

12x + 20 - x = - 2

11x = - 22

x = - 2

y = 3 * - 2 + 5

y = - 5 + 5

y = 0

Step-by-step explanation:

A. y = - x+5 (equation no. 1)

x+2y=2 (equation no. 2)

On substituting 1 in 2, we get,

x+2 (-x+5) = 2

x-2x+10=2

-x+10=2

x=8

Put x=8 in any of the equations and find y

B. y=3x+5 (equation no. 1)

4y-x=-2 (equation no. 2)

On substituting 1 in, we get,

4 (3x+5) - x=-2

12x+20-x=-2

11x+20=-2

11x=-22

x=-2

Put x=-2 in any of the equations and find y