What are the values that make x^2 + bx + 64 a perfect square?

b = ±16

Step-by-step explanation:

Normally to find the number we add to make it a perfect square

We take the coefficient of x

b

Divide by 2

b/2

Then square it

(b/2) ^2

In this case, we are adding 64

(b/2) ^2 = 64

Take the square root of each side

sqrt ((b/2) ^2) = sqrt (64)

b/2 = ±8

Multiply each side by 2

b/2*2 = ±8 * 2

b = ±16