Find all zeros and write in factored form

(x-5) (3x^2-8x+6) = 0

x = 5, 4/3+i√2/3, 4/3-i√2/3.

Step-by-step explanation:

(x-5) (3x^2-8x+6) = 0

This is in factored form already. 3x^2 - 8x + 6 cannot be factored, it is prime.

One zero is x = 5.

3x^2-8x+6 = 0 Using the quadratic formula:

x = [8 + / - sqrt (64 - 4*3*6]) / 6

x = 4/3 + / - sqrt (-8) / 6

x = 4/3 + / - 2sqrt2 i / 6

x = 4/3 + / - i√2 / 3.