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1 March, 13:58

the length of a rectangle is 4 feet longer than twice the width of the same rectangle. if the perimeter of the rectangle is 68 feet, what are the dimension (the length and width) of the rectangle?

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  1. 1 March, 14:25
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    Represent the length and width by L and W. Then L = W + 4.

    Using the perimeter formula: P = 2L + 2W = 68 ft = 2W) + 2 (W+4).

    Solve for W: 68 = 2W + 2W + 8, or 4W = 60. Thus, W = 15 and L = 19.

    The dimensions of the rectangle are 15 by 19 feet.
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