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19 December, 02:56

Select the correct answer. What is the solution set of x2 + y2 = 26 and x - y = 6?

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  1. 19 December, 04:46
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    (1, - 5) and (5, - 1)

    Step-by-step explanation:

    Given the 2 equations

    x² + y² = 26 → (1)

    x - y = 6 → (2)

    Rearrange (2) making x the subject by adding y to both sides

    x = 6 + y → (3)

    Substitute x = 6 + y into (1)

    (6 + y) ² + y² = 26 ← expand (6 + y) ² and simplify left side

    36 + 12y + y² + y² = 26

    2y² + 12y + 36 = 26 (subtract 26 from both sides)

    2y² + 12y + 10 = 0 (divide through by 2)

    y² + 6y + 5 = 0 ← in standard form

    (y + 5) (y + 1) = 0 ← in factored form

    Equate each factor to zero and solve for y

    y + 5 = 0 ⇒ y = - 5

    y + 1 = 0 ⇒ y = - 1

    Substitute these values into (3) for corresponding values of x

    x = - 5 : x = 6 - 5 = 1 ⇒ (1, - 5)

    x = - 1 : x = 6 - 1 = 5 ⇒ (5, - 1)
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