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5 March, 18:54

Find the perimeter of a rectangle with length 7x - 2 and width 5x^2 + 1.

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  1. 5 March, 21:56
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    10x^2 + 14x - 2

    Step-by-step explanation:

    So for the perimeter, you have to solve 2 (7x-2) + 2 (5x^2+1)

    So distribute the 2s on both s we get 14x - 4 + 10x^2 + 2

    This in standard form is 10x^2 + 14x - 2
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