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20 April, 10:27

when the length of a rectangle is X inches and the width is y inches, the perimeter is 30 inches. if the length is tripled and the width is quadrupled the perimeter becomes 102 inches. find the length and width of the original rectangle

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  1. 20 April, 12:34
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    P1=2x+2y=30

    after modify them

    P2=2*3x+2*4y=102

    6x+8y=102

    2x+2y=30 / * (-3)

    -6x-6y = - 90

    6x+8y=102

    we must add the 2 expressions

    / 8y-6y=102-90

    2y=12

    y=12:2

    y=6

    2*x+2*y=30

    2x+2*6=30

    2x+12=30

    2x=30-12

    2x=18

    x=18:2

    x=9
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