when the length of a rectangle is X inches and the width is y inches, the perimeter is 30 inches. if the length is tripled and the width is quadrupled the perimeter becomes 102 inches. find the length and width of the original rectangle

Question

Mathematics

Calvin

20 April, 10:27

when the length of a rectangle is X inches and the width is y inches, the perimeter is 30 inches. if the length is tripled and the width is quadrupled the perimeter becomes 102 inches. find the length and width of the original rectangle

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Answers (1)

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Jamal Webster · Answer 1

P1=2x+2y=30

after modify them

P2=2*3x+2*4y=102

6x+8y=102

2x+2y=30 / * (-3)

-6x-6y = - 90

6x+8y=102

we must add the 2 expressions

/ 8y-6y=102-90

2y=12

y=12:2

y=6

2*x+2*y=30

2x+2*6=30

2x+12=30

2x=30-12

2x=18

x=18:2

x=9