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25 August, 06:48

Solve the system of equations algebraically.

4x-2y=4

6x-4y=6

a. no solution

b. many solutions

c. (0,1)

d. (1,0)

+2
Answers (2)
  1. 25 August, 08:42
    0
    Choice d is correct answer.

    Step-by-step explanation:

    We have given a system of equations.

    4x-2y = 4 eq (1)

    6x-4y = 6 eq (2)

    We have to solve it for x and y.

    We use method of elimination to solve this system.

    Multiplying by 2 to both sides of eq (1), we have

    2 (4x-2y) = 2 (4)

    8x-4y = 8 eq (3)

    Subtracting eq (3) to eq (2), we have

    8x-4y - (6x-4y) = 8-6

    8x-4y-6x+4y = 2

    2x = 2

    Dividing by 2 to both sides of qbove equation, we have

    2x/2 = 2/2

    x = 1

    Putting the value of x in eq (1), we have

    4 (1) - 2y = 4

    4-2y = 4

    Adding - 4 to both sides of above equation, we have

    -2y = 0

    Dividing by - 2 to both sides of above equation, we have

    y = 0

    Hence, the solution of given system is (1,0).
  2. 25 August, 10:29
    0
    Option (d) is correct.

    (1, 0) is the solution of the given system of equation.

    Step-by-step explanation:

    Consider the given system of equation

    4x - 2y = 4 ... (1)

    6x - 4y = 6 ... (2)

    We have to solve the system algebraically,

    We will solve it by elimination method,

    Multiply equation (1) by 2, we get,

    (1) ⇒ 8x - 4y = 8 ... (3)

    Subtract equation (2) from (3), we get,

    8x - 4y - (6x - 4y) = 8 - 6

    8x - 4y - 6x + 4y = 2

    8x - 6x = 2

    ⇒ x = 1

    Substitute x = 1 in (1) and solve for y, we get,

    ⇒ 4x - 2y = 4 ⇒ 4 (1) - 2y = 4 ⇒ 2y = 4 - 4 ⇒ 2y = 0 ⇒ y = 0

    Thus, (1, 0) is the solution of the given system of equation.

    Option (d) is correct.
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