What is the volume of a hemisphere with a diameter of 57.2 in, rounded to the nearest tenth of a cubic inch?

48,970.7 in³

Step-by-step explanation:

If the diameter is 57.2 in, then the radius is half that, or 28.6 in.

The volume of a sphere is V = (4/3) πr³, and so the volume of this hemisphere is (2/3) πr³.

Substituting 28.6 in for r, we get the final answer:

(2/3) (3.14) (28.6) ³ in³, or (to the nearest tenth of a cubic inch), 48,970.7 in³