Write the smaller solution first, and the larger solution second.

f (x) = (x - 3) (2x - 8)

smaller x=

larger x=

x = 3, x = 4

Step-by-step explanation:

Given

f (x) = (x - 3) (2x - 8)

To find the solutions let f (x) = 0, that is

(x - 3) (2x - 8) = 0

Equate each factor to zero and solve for x

x - 3 = 0 ⇒ x = 3

2x - 8 = 0 ⇒ 2x = 8 ⇒ x = 4

Thus

smaller solution x = 3

larger solution x = 4

x = 3, x=4

Step-by-step explanation:

easy, make each parentheses equal to 0.

so (x-3) = 0

(2x-8) = 0

then now solve for x in each case