Find the vertex of the function given below.

y = x2 - 6x + 1

V (3, - 8)

Step-by-step explanation:

Parable equation is of the form:

(x - h) ² = 4p * (y - k)

In that expression, vertex has coordinates V (h, k)

Then all we have to do is transform the given equation

y = x² - 6x + 1 or x² - 6x = y - 1 (1)

We can get a perfect square trinomial in the first member of the equation according to:

x² - 6x = (x - 3) ² - 9

(x - 3) ² = x² - 6x + 9

By substitution en equation (1)

(x - 3) ² - 9 = y - 1

(x - 3) ² = y - 1 + 9

(x - 3) ² = y + 8

(x - 3) ² = (y + 8)

Then vertex coordinates are

V (3, - 8)