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27 January, 16:59

Write equation for the line in slope intercept form (6,4) and (3,8)

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  1. 27 January, 20:07
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    Answer: y = - 4x/3 + 12

    Step-by-step explanation:

    The equation of a straight line can be represented in the slope-intercept form, y = mx + c

    Where c = y intercept

    m represents the slope of the line.

    m = (y2 - y1) / (x2 - x1)

    y2 = final value of y

    y 1 = initial value of y

    x2 = final value of x

    x1 = initial value of x

    The line passes through (6, 4) and (3, 8),

    y2 = 8

    y1 = 4

    x2 = 3

    x1 = 6

    Slope, m = (8 - 4) / (3 - 6) = 4 / - 3 = - 4/3

    To determine the y intercept, we would substitute x = 3, y = 8 and m = - 4/3 into y = mx + c. It becomes

    8 = - 4/3 * 3 + c

    8 = - 4 + c

    c = 8 + 4

    c = 12

    The equation becomes

    y = - 4x/3 + 12
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