Ask Question
27 September, 20:10

A mountain bike tire completes 40 revolutions and travels 272 feet. Rounded to the nearest inch, what is the diameter of the bike's tire? Use 3.14 for pi.

+4
Answers (1)
  1. 27 September, 20:23
    0
    26 inches

    Explanation:

    When the tire does not slip, each revolution means that the bike advance a distance equal to the circumference of the tire.

    Thus, when 40 revolutions are completed, the bike will advance a distance equal to 40 times the circumference of the bike:

    distance = 40 * circumference

    The circumference is equal to:

    circumference = 2π * radius

    Using π = 3.14:

    272 feet = 40 * 2 * 3.14 * radius

    radius = 1.0828 feet

    diameter = 2 * radius = 2.1656 feet

    Convert to inches: 1 feet = 12 inches:

    diameter = 2.1656 feet * 12 inches/feet = 25.9872 inches ≈ 26inches
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A mountain bike tire completes 40 revolutions and travels 272 feet. Rounded to the nearest inch, what is the diameter of the bike's tire? ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers