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27 December, 03:46

Find the equation of a circle that has its center at (6,-4) and has a radius of 3.

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Answers (2)
  1. 27 December, 04:01
    0
    (x-6) ^2 + (y+4) ^2 = 9

    Step-by-step explanation:

    The equation of a circle is given by

    (x-h) ^2 + (y-k) ^2 = r^2 where (h, k) is the center and r is the radius

    (x-6) ^2 + (y - - 4) ^2 = 3^2

    (x-6) ^2 + (y+4) ^2 = 3^2

    (x-6) ^2 + (y+4) ^2 = 9
  2. 27 December, 05:24
    0
    I think it's 9 but not sure
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